WebJan 22, 2024 · Contents in this project Find and Remove Special Characters From String in Flutter Dart :- 1. Open your project’s main.dart file and import material.dart package. 1 import 'package:flutter/material.dart'; 2. Creating our main runApp () method, Here we would call our main MyApp class. 1 void main() = > runApp(MyApp()); 3. WebJul 24, 2024 · 6 Answers. Sorted by: 71. You can use String.indexOf combined with String.substring: void main () { const str = "the quick brown fox jumps over the lazy dog"; const start = "quick"; const end = "over"; final startIndex = str.indexOf (start); final endIndex = str.indexOf (end, startIndex + start.length); print (str.substring (startIndex + start ...
Exploring String methods in Dart - Medium
WebJan 20, 2024 · You can use the subString method from the String class. String s = "one.two"; //Removes everything after first '.'. String result = s.substring (0, s.indexOf ('.')); print (result); In case there are more than one '.' in the String it will use the first occurrance. WebFeb 15, 2012 · Then you can have an extension to properly iterate a String using both simple characters or Unicode graphemes: extension on String { /// To iterate a [String]: `"Hello".iterable()` /// This will use simple characters. If you want to use Unicode Grapheme /// from the [Characters] library, passa [chars] true. ironically in the united states
flutter - Get first few words of a String in dart - Stack Overflow
WebSep 22, 2024 · So instead of having to create the responses "good, "good thanks", "great" and "great thanks", if the word thanks is in the reply it will just remove it and will only have to look for "good" or "great" I got the removing the word part from another website but I don't think I am using it correctly. Here is my code so far. WebMar 21, 2024 · extension StringExtension on String { String deleteLastChar ( {int toDelete = 1}) => substring (0, length - toDelete); } And you can use like "12:00 AM".deleteLastChar (toDelete: 3) // Prints 12:00 Why toDelete: 3? Because you also want to remove the space between 12:00 and AM Share Follow answered Mar 21, 2024 at 7:51 Yayo Arellano … WebDec 7, 2024 · void main () { String text = "Hello your number is: 1234567890"; var aString = text.replaceAll (RegExp (r' [^0-9]'), ''); var aInteger = int.parse (aString); print ( "The number provided is :" + aInteger.toString (), ); } Your Output: The number provided is :1234567890 Share Improve this answer Follow answered Dec 7, 2024 at 12:17 ironically in the united