Web21 jan. 2015 · Sorted by: 7. Here's how I would do it with a for expression. for ( i <- 1 to 1000 if i % 3 == 0 i % 5 == 0) yield i. This gives: scala.collection.immutable.IndexedSeq [Int] … WebYes, a 10-digit number in the international place value system is called a billion, because the place name of the 10 th digit from the right is called a billion. For example, 3,000,000,000 is read as three billion. What is the Largest 10-Digit Number? The largest 10 digit number is 9,999,999,999.
Divisibility Calculator Free Online Tool to check the Divisibility ...
WebAs per the Divisibility Rule of 3, a number is completely divisible if the sum of the digits in it is divisible by 3 or a multiple of 3. For example, let us take 324. Sum of digits = 3+2+4 … WebMetric prefix. A metric prefix is a unit prefix that precedes a basic unit of measure to indicate a multiple or submultiple of the unit. All metric prefixes used today are decadic. Each prefix has a unique symbol that is prepended to any unit symbol. The prefix kilo-, for example, may be added to gram to indicate multiplication by one thousand ... dewalt impact hex bit set
Given a list of digits, construct the largest number divisible by 3
WebWe know as per the divisibility rule of 3, that a number is divisible only if the sum of digits is divisible by 3 or a multiple of 3. Sum of digits = 4+2+8 = 14 Now dividing 14÷3 we have the remainder of 2. As 14 is not completely divisible by 3 we can say that 428 is not divisible by 3. Example 2. Check if 516 is divisible by 3. Solution: Web25 feb. 2024 · As we have to find the sum of numbers divisible by 2 or 5. So, the required sum is given by- sum = sum_2 + sum_5 – sum_10 Algorithm: Step 1: Start Step 2: Create a function with the return type of long and input parameter of int type, find sum will return the sum of numbers divisible by 2 or 5 up to N. Web30 jul. 2024 · Below is my code to write a python program to print all the numbers divisible by 3 and 5 − lower = int(input("Enter lower range limit:")) upper = int(input("Enter upper range limit:")) for i in range(lower, upper+1): if( (i%3==0) & (i%5==0)): print(i) Output Enter lower range limit:0 Enter upper range limit:99 0 15 30 45 60 75 90 church of christ in europe